The atomic clocks that you can purchase are sent a signal via satellite from the real atomic clocks which are cesium oscillators (they keep time by measuring the rate of decay of cesium atoms which is the metric standard for 1 second.) Your atomic clock is just a receiver. It you want to check yours for accuracy just look up an atomic clock server on the web.
how are clocks of gps receiver are synchronized with the precise atomic clock of the GPS?
The short answer is you don't need to synchronise the clock on the GPS receiver with the clocks on the satellites. For example:
It is exactly 12 midday. You look at the signals from two satellites.
Satellite 1's signal says 'I'm located at this position in my orbit and the time is 12.00.00'
Satellite 2's signal says 'I'm at this position and the time is 11.59.59'
The atomic clocks in the satellites are synchronised (at least in the sense that they are extremely accurate). But the times read by the reciever will not be the same because of the slight delay in that signal arriving. In the above case, Satellite 2 is further way so the signal you recieve is offset from that of Satellite 1. You're getting, if you like, the last tick of the clock on Satellite 2 because the current 12.00.00 tick signal is still in transit to you.
The GPS signal contains information about where the satellites are. What the receiver does is take the known position of satellite 1 and the known position of satellite 2, and then work out where on the earth's surface it would have to be to get a 1 second delay (for the purposes of the example) in the signal. That only gives you one position, so you need at least another satellite to pinpoint your location. And of course the delays are extremely small.
How do I get my computer to synch up with my atomic clock?
windows 2000/XP has the option to sync your time to an internet server but i don't think that will work so well, maybe if your computers are part of a domain controller then they're time will always be exactly the same.
to enable internet time double click on the time in of the startmenu task bar. click the tab INTERNET TIME and check the box AUTOMATICALLY SYNCRONIZ WITH AN INTERNETTIME SERVER.
see if that works otherwise try nettime although it is outdated.
How do you set the Discovery Channel atomic clock?
Hi, you put the batteries back in and in a few hours it will set the time correctly. It doesn't use a satellite--just a local radio station, but it can take several hours to actually work. If the unit doesn't reset its time within one day put it next to a window and it should reset itself properly. Putting it next to a window allows the unit to receive the radio signal a lot better.
What time does an Atomic Clock reset itself for Daylights Savings?
They don't. UTC (coordinated universal time) just advances forward at one second per second. It never jumps forward or back an hour. The time zones themselves change their offset from UTC, so CST is -5, while CDT is -6.
The official clocks do occasionally add leap seconds at the end of a day (23:59:60) to account for the gradual slowing of the rotation of the earth.
How much time will an astronaut's atomic clock have lost during a total trip that takes 10 days?
This problem requires general relativity. A moving clock runs slow, but a clock higher up in a gravitational field will run faster, which cancels it out somewhat.
If a clock in orbit ticks off a proper time t0, the time ticked off by a distant observer is:
tf = t0 / sqrt (1 - 3GM / rc^2)
The time ticked off on earth (not orbiting, and close enough to stationary) is:
tearth = tf * sqrt (1 - 2GM/Rc^2)
= t0 * sqrt ( (1 - 2GM/Rc^2) / (1 - 3GM/rc^2) )
So you can look up Newton's big G, the mass of the earth(M), its radius(R), and the speed of light (c).
They don't give you the orbital radius(r), but do give you the speed(v) and period(T):
v = 2 pi r / T
So the radius is:
r = vT / 2pi
So your answer is:
time lost = t0 (1 - sqrt ( (1 - 2GM/Rc^2) / (1 - 6 pi GM/vTc^2) ) )
Compare that to what you get for simple time dilation of a clock moving in a straight line away from gravity:
time lost = t0 (gamma - 1)
= t0 ( sqrt (1 / (1 - (v/c)^2) ) - 1)
Note that if this is homework from an undergrad sophomore- or junior-year modern physics class, your prof probably expects the answer down below, since you haven't learned anything about general relativity.