Can someone help me solve this problem?

g => (1/3) * b g <= (1/4) * c t + p => 21 Without any more information, you can't do any better than (1/3) * b <= g <= (1/4) * c Assuming at least one bulldog has registered, if b = 1, g must be at least 1 (because you can't have 1/3) of a golden retriever), and c must be at least 4.

So what's this I hear about a double merle collie winning Best of show?

http://answers.yahoo.com/question/index;_ylt=An7j5tJswDQkvYQZ_OtHTsPsy6IX;_ylv=3?qid=20120213160532AAjkxaE I asked a similar question you may be interested in the answers I got so i link it above. Funny some of the posters who supported this dogs win have since removed their posts, maybe they are finally coming to see what hypocrites they are. I have no idea how anyone can say this is OK & to say it's a dog show & the judge is just going on whats in front of them is a load of bull. They know this dogs breeding & by placing it so highly it's condoning double merle breeding's in my honest opinion. What happen to breeding for function, health, temperament & then for standard type & color? That's how you breed healthy dogs able to for fill their original function but no extreme type & flashy colors wins ribbons so bugger the rest. Very sad day for dog showing & breeding!!

Westminster strikes again, what do you think of this?

Ms. Betty Regina Leininger 2012 Westminster dress?

Can someone help me solve this problem?

You need to review your past answers. **** http://answers.yahoo.com/question/index?qid=20111213150038AA6Wggn g => (1/3) * b g <= (1/4) * c t + p => 21 Without any more information, you can't do any better than (1/3) * b <= g <= (1/4) * c Assuming at least one bulldog has registered, if b = 1, g must be at least 1 (because you can't have 1/3) of a golden retriever), and c must be at least 4.

Why are dog lovers against Mitt Romney.?

All the dog owners who named there dog " mitt",have to think of another one.

2012 Westminster Dogshow Problem Help? REVISED?

Let g be golden retriever, etc. (1) g <= (1/4) * c (2) g >= (1/3) * b (3) g + b >= 21 g = 6 and b = 15 is the optimal way to satisfy (2) and (3) while keeping (3) in mind because we want to minimize g and hence c. 6 is at most (1/4) of 24. g = 6, b = 15, c = 24 <-------- Answer .

Westminster dog show, do they really care?

Knowingly breeding Merle to Merle is unethical and has been banned in kennel clubs and breed clubs across Europe and elsewhere outside the US. Even in the US, there are breed clubs that know better and ban merle to merle, dapple to dapple, etc. Wyndlair Avalanche is a travesty and his breeders should not be rewarded for intentionally creating a defective dog who is blind and deaf (I love the answer that says he's just mostly blind! yeah, that's a great excuse!) just to create a few more merle puppies per litter. This sire is the #1 producer now and he has never won anything. What a joke! A blind, deaf, poorly built dog is THE NUMBER 1 SIRE in the breed, he has never seen the inside of a show ring, he's never SEEN anything actually, and yet he is the dog all the wannabes want to breed to their bitches. Why? Because Rough Collies are corrupt and have fallen from grace. Sure, this is a dog show and the judge *might* not know this dog's history. This dog SHOULD NEVER have even existed. It should never have been bred. THAT is the issue. I also don't buy that no one knows. This dog and other Wyndlair Avalanche offspring have benefited from hundreds of thousands of dollars in advertisements! This is the number one stud dog, the grandson of last generation's number 1 stud dog. This is NOT a backyard breeder, this is the CREAM of the crop. If the judge didn't know who this dog was (and how could that happen, this is not their first dog show!), it doesn't matter. WE know who this dog is and that is the point. We won't reward this unethical breeding with praise for getting a ribbon when the price they paid for that ribbon is a disabled handicap dog that will never see and probably can't hear much either. And it didn't have to be that way.